Plumbers NZ is New Zealand's largest online plumbing, gas and drainage resource. Plumbing exam help, plumbing news, directory and free quotes.

Question 8

« Question 11 | Question 6 »

0 Members and 1 Guest are viewing this topic.

Print
Go Down Pages1
User actions

LisaS

March 14, 2009, 11:54:49 AM
QUESTION 8
Calculate the amount of material required to fill a trench having the following dimensions:
  125 m long × 0.725 m wide with a depth of 0.720 m at the top end of the trench
and 1.735 m at the bottom
Your answer should include an allowance of 34% for compaction.
(Show ALL working.)
Formula: Volume = Length × Width × average depth
           
           
           
           
           
           
           
           
           
           
(5 marks)
Total 5 marks

Linkback: https://forum.plumbers.nz/drainlaying-exam-2006/24/question-8/181/
    Share Post |

Plumber

#1
March 26, 2009, 10:36:26 AM
First calculate average depth: (0.720 + 1.735 / 2 ) = 1.2275 (rounded up) = 1.23

125 m long x 0.725 m wide x 1.23 average depth = 111.47 m³

111.47³ + 34% (111.47³ x 0.34) =  37.90³ (for compaction)

37.90³ + 111.47³ = 149.37 m³



    Share Post |
Please note that the advice I am giving is only my opinion and not necessarily a fact.  Please refer to our terms and conditions.
Print
Go Up Pages1

* Share Topic

Share via digg Share via facebook Share via linkedin Share via twitter
User actions

Share this topic...

In a forum
(BBCode)
In a site/blog
(HTML)

Similar topics (5)